15x^2-1050x+3600=0

Solution for 15x^2-1050x+3600=0 equation:

15x^2-1050x+3600=0

a = 15; b = -1050; c = +3600;
Δ = b2-4ac
Δ = -10502-4·15·3600
Δ = 886500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{886500}=\sqrt{900*985}=\sqrt{900}*\sqrt{985}=30\sqrt{985}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1050)-30\sqrt{985}}{2*15}=\frac{1050-30\sqrt{985}}{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1050)+30\sqrt{985}}{2*15}=\frac{1050+30\sqrt{985}}{30}
$